REAL 1Z1-071 LATEST PRACTICE & 1Z1-071 FREE QUESTIONS - 1Z1-071 TESKING VCE

Real 1z1-071 Latest Practice & 1z1-071 Free Questions - 1z1-071 Tesking Vce

Real 1z1-071 Latest Practice & 1z1-071 Free Questions - 1z1-071 Tesking Vce

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Oracle 1z0-071 Certification Exam is a valuable credential for individuals who are looking to advance their career in the database management field. Oracle Database SQL certification is recognized globally and is highly valued by employers. It is also a prerequisite for other Oracle certifications, such as the Oracle Database 12c Administrator Certified Associate and the Oracle Database 12c Administrator Certified Professional. Passing 1z1-071 Exam is not easy and requires a strong understanding of SQL and Oracle Database 12c, but it can open up many doors for IT professionals looking to advance their career.

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Basic information about the Oracle 1Z0-071 Exam:

Oracle 1Z0-071 Exam is a new Oracle certification exam that tests the ability of an individual to understand and use Oracle database concepts and tools required for performing administration functions. This exam will be administered by participating Oracle Partner Programs (OPP) members worldwide. OPP members administer some or all of these exams as components of their service offering, which might include implementation, implementation support, consulting services, training and development, application development, and testing.

It is an Oracle OCA certification exam that can be taken by individuals who are working in any IT-related field or business role where data using and management is a primary component of their job including IT architects, database administrators, software developers, testers, and marketers among others. The exam is designed to assess your competence at any phase of the Oracle database lifecycle, including the design, development, implementation, upgrade, and management of databases. The exam is made up of 78 multiple choice questions; you will have 120 minutes to answer the 78 questions.

You must take this test at an authorized testing center. You may register for this exam online at Oracle Certification. Please be aware that you are only allowed to take 1 Oracle certification exam per 12 months so plan accordingly if you are preparing for multiple exams. You are also allowed to have 1 retake for this particular test within 12 months of the first administration date. If you want to pass the exam successfully you have to do preparation. Oracle 1Z0-071 Dumps will help you to get prepared for the Oracle 1Z0-071 exam. You need to have a smarter & maintained framework for the preparation of exam 1Z0-071 and testking pattern.

Oracle 1z0-071 exam is intended for SQL developers, database administrators, and IT professionals who work with Oracle databases. 1z1-071 Exam consists of 73 multiple-choice questions that need to be completed within two hours. 1z1-071 exam is available in several languages, including English, Japanese, and Chinese. 1z1-071 exam can be taken either in-person at a Pearson VUE testing center or online from your home or office.

Oracle Database SQL Sample Questions (Q193-Q198):

NEW QUESTION # 193
Examine the data in the CUST_NAME column of the CUSTOMERS table.
CUST_NAME
-------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikkilineni
Julia Nayer
You need to display customers' second names where the second name starts with "Mc" or "MC".
Which query gives the required output?

  • A. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
    INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1)) = INITCAP('MC%');
  • B. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
    SUBSTR(cust_name, INSTR(cust_name,' ')+1) LIKE INITCAP('MC%');
  • C. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
    INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1)) LIKE 'Mc%';
  • D. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
    INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1))='Mc';

Answer: C


NEW QUESTION # 194
Examine the description of the TRANSACTIONStable:

Which two SQL statements execute successfully?
SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount + 100

  • A. transactions;
    SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount + 100
  • B. "DUES" FROM transactions;
    SELECT customer_id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount +
  • C. 100 "DUES AMOUNT" FROM transactions;
    SELECT customer_id CUSTID, transaction_date TRANS_DATE, amount +100 DUES FROM
  • D. 'DUES' FROM transactions;
  • E. DUES FROM transactions;
    SELECT customer_id AS 'CUSTOMER-ID', transaction_date AS DATE, amount + 100

Answer: A,E


NEW QUESTION # 195
Examine the structure of the MEMBERStable:

You want to display details of all members who reside in states starting with the letter A followed by exactly one character.
Which SQL statement must you execute?
SELECT * FROM MEMBERS WHERE state LIKE '%A_';

  • A.
  • B. SELECT * FROM MEMBERS WHERE state LIKE 'A_%';
  • C. SELECT * FROM MEMBERS WHERE state LIKE 'A%';
  • D. SELECT * FROM MEMBERS WHERE state LIKE 'A_';

Answer: B


NEW QUESTION # 196
Examine the description of the ENPLOYES table:

Which query requires explicit data type conversion?

  • A. SELECT join _ date FROM employees WHERE join date > *10-02-2018';
  • B. SELECT salary + '120.50' FROM employees;
  • C. SELECT join_ date||''|| salary FROM employees;
  • D. SELECT SUBSTR(join date, 1, 2) - 10 FROM employees;
  • E. SELECT join_ date + '20' EROM employees;

Answer: A

Explanation:
A look at the queries and how Oracle Database handles data type conversion:
A: This statement takes a substring of the JOIN_DATE column. Since JOIN_DATE is a DATE type and SUBSTR function expects a string, implicit conversion will occur from DATE to string based on the NLS_DATE_FORMAT setting. However, this will not require explicit conversion in the query itself.
B: This statement tries to add '20' to JOIN_DATE. Oracle Database does not support adding a string to a DATE implicitly. An explicit conversion of '20' to a number is required, or using the INTERVAL keyword to add days or years as appropriate.
C: This statement concatenates the date with an empty string and the salary. The database will implicitly convert the JOIN_DATE from a DATE to a string using the NLS_DATE_FORMAT setting and then perform the concatenation.
D: This query attempts to compare a DATE column with a string literal '*10-02-2018'. An explicit conversion using TO_DATE is needed to convert the string to a DATE data type with the appropriate date format mask. In this case, because the string does not follow the NLS_DATE_FORMAT 'DD-MON-YY', it will not be implicitly converted correctly.
E: This statement adds '120.50' to SALARY. Oracle Database will implicitly convert the string '120.50' to a number before performing the arithmetic addition, as SALARY is a NUMBER data type.


NEW QUESTION # 197
Examine this SQL statement:

Which two are true?

  • A. The subquery is executed for every updated row in the ORDERS table.
  • B. The subquery is executed before the UPDATE statement is executed.
  • C. The UPDATE statement executes successfully even if the subquery selects multiple rows.
  • D. All existing rows in the ORDERS table are updated.
  • E. The subquery is not a correlated subquery.

Answer: A,B

Explanation:
The provided SQL statement is an update statement that involves a subquery which is correlated to the main query.
A . The subquery is executed before the UPDATE statement is executed. (Incorrect) This statement is not accurate in the context of correlated subqueries. A correlated subquery is one where the subquery depends on values from the outer query. In this case, the subquery is executed once for each row that is potentially updated by the outer UPDATE statement because it references a column from the outer query (o.customer_id).
B . All existing rows in the ORDERS table are updated. (Incorrect)
Without a WHERE clause in the outer UPDATE statement, this would typically be true. However, the correctness of this statement depends on the actual data and presence of matching customer_id values in both tables. If there are rows in the ORDERS table with customer_id values that do not exist in the CUSTOMERS table, those rows will not be updated.
C . The subquery is executed for every updated row in the ORDERS table. (Correct) Because the subquery is correlated (references o.customer_id from the outer query), it must be executed for each row to be updated in the ORDERS table to get the corresponding cust_last_name from the CUSTOMERS table.
Reference:
D . The UPDATE statement executes successfully even if the subquery selects multiple rows. (Incorrect) The subquery inside the SET clause must return exactly one value for each row to be updated. If the subquery returns more than one row for any outer row, the UPDATE statement will result in an error (specifically, an "ORA-01427: single-row subquery returns more than one row" error).
E . The subquery is not a correlated subquery. (Incorrect)
This is incorrect because the subquery references the o.customer_id column from the ORDERS table, which makes it a correlated subquery.
The correct answers are A and C. The subquery is a correlated subquery because it references the ORDERS table's customer_id in its WHERE clause. It is executed for each row to be updated since it depends on values from the outer query (the o.customer_id). It's important to note that although the statement A is marked incorrect based on the typical behavior of correlated subqueries, in some cases, Oracle's optimizer may unnest the subquery and execute it beforehand if it determines that it's more efficient and the result is the same. However, this doesn't change the nature of the query being a correlated subquery.


NEW QUESTION # 198
......

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